I'm sure many of you have heard this question.
You have two buckets, one 3 gallon and one five gallon, and a water hose. I'm talking about U.S. gallons, here.
You want to get 4 gallons of water.
How do you do it?
The question is something like that.
Most of us know the answer, but would it be cheating if you used the fact that a U.S. Gallon weighs approximately 8.3 pounds, and therefore you could weigh the five gallon bucket, set that at 0, and fill the bucket (while the bucket is on a scale) with just over 33 pounds of water?
I also came up with a simple math formula for this.
Let V1 = 3
Let V2 = 5
R is the result.
So, R = (2(V1) - V2) + V1
If you plug in the numbers, you get:
R = [2(3) - 5] + 3
R = (6 - 5) + 3
R = 1 + 3
R = 4
You have two buckets, one 3 gallon and one five gallon, and a water hose. I'm talking about U.S. gallons, here.
You want to get 4 gallons of water.
How do you do it?
The question is something like that.
Most of us know the answer, but would it be cheating if you used the fact that a U.S. Gallon weighs approximately 8.3 pounds, and therefore you could weigh the five gallon bucket, set that at 0, and fill the bucket (while the bucket is on a scale) with just over 33 pounds of water?
I also came up with a simple math formula for this.
Let V1 = 3
Let V2 = 5
R is the result.
So, R = (2(V1) - V2) + V1
If you plug in the numbers, you get:
R = [2(3) - 5] + 3
R = (6 - 5) + 3
R = 1 + 3
R = 4
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